在老外的站上看到解决的好方法,故简单编译之:
在一个asp.net 的应用中,经常要动态修改页面的标题,一个典型的例子就是,在一个页面导航的控件中,希望用户点选哪一个连接,在页面的title里就显示相关的内容,举个例子,比如一个网站,有如下的网站架构:
有图书分类,下面再有中国图书,外国图书分类,则一般可以用树形或者asp.net 2.0的新增加的导航栏控件
(sitemap),来实现,比如
图书--->中国图书;
图书---->外国图书
等,而如果这个时候,能在页面的
部分,也能显示比如"图书-->中国图书"这样,那就更加直观明显了,<br>在asp.net 2.0中,我们可以使用<head>部分的服务端控件来实现了,首先,要添加标记<br><head runat="server"></p>
<p>然后可以在page_load事件中,以如下形式改边其title的内容了,如<br>Page.Header.Title = "The current time is: " & DateTime.Now.ToString() <br>,也可以简单写成page.title.</p>
<p>然后,我们可以通过这样的办法,将其于sitemap控件结合了,实现方法如下:</p>
<p>Const DEFAULT_UNNAMED_PAGE_TITLE As String = "Untitled Page"<br> Const DEFAULT_PAGE_TITLE As String = "Welcome to my Website!!"</p>
<p><br> Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load<br> 'Set the page's title, if needed<br> If String.IsNullOrEmpty(Page.Title) OrElse Page.Title = DEFAULT_UNNAMED_PAGE_TITLE Then<br> If SiteMap.CurrentNode Is Nothing Then<br> Page.Title = DEFAULT_PAGE_TITLE<br> Else<br> Page.Title = GetPageTitleBasedOnSiteNavigation()</p>
<p> 'Can also use the following if you'd rather<br> 'Page.Title = GetPageTitleBasedOnSiteNavigationUsingRecursion(SiteMap.CurrentNode)<br> End If<br> End If<br> End Sub</p>
<p> Private Function GetPageTitleBasedOnSiteNavigation() As String<br> If SiteMap.CurrentNode Is Nothing Then<br> Throw New ArgumentException("currentNode cannot be Nothing")<br> End If</p>
<p> 'We are visiting a page defined in the site map - build up the page title<br> 'based on the site map node's place in the hierarchy</p>
<p> Dim output As String = String.Empty<br> Dim currentNode As SiteMapNode = SiteMap.CurrentNode</p>
<p> While currentNode IsNot Nothing<br> If output.Length > 0 Then<br> output = currentNode.Title & " :: " & output<br> Else<br> output = currentNode.Title<br> End If</p>
<p> currentNode = currentNode.ParentNode<br> End While</p>
<p> Return output<br> End Function</p>
<p>在上面的代码中,首先预定义了两个常量,然后逐步建立sitemap的结点,一开始结点是null的，然后再调用<br>GetPageTitleBasedOnSiteNavigation() 这个过程,在每建立一个sitemap的结点时,用字符串进行连接,最后返回给page.title即可实现,当然也可以用递归实现</p>
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