ajaxSubmit插件jQuery1.4.2版JSON问题
作者:互联网
2010-09-09
jQuery Form 插件基于jQuery v1.4.2版返回JSON数据时一直报错;修改以下内容可恢复;
原后台输出数据格式如:{sitename:'开发者网络',siteurl:'www.AAA.net',level:10} 需改为 {"sitename":"开发者网络","siteurl":"www.AAA.net","level":10}
也就是在名称需以双引号包括;因为 jQuery 1.4.2版在 parseJSON 方法中添加了正则判断
| if ( /^[],:{}s]*$/.test(data.replace(/\(?:[", "@") .replace(/"[^", "]") .replace(/(?:^|:|,)(?:s*[)+/g, "")) ) { // Try to use the native JSON parser first } else { |
jQuery Form 插件需要修改的地方
| if (scr || s.textarea) { // see if user embedded response in textarea var ta = doc.getElementsByTagName('textarea')[0]; if (ta) { xhr.responseText = ta.value; } else if (scr) { // account for browsers injecting pre around json response var pre = doc.getElementsByTagName('pre')[0]; if (pre) { xhr.responseText = pre.innerHTML; } } } else if (s.dataType == 'xml' && !xhr.responseXML && xhr.responseText != null) { xhr.responseXML = toXml(xhr.responseText); } |
修改为:
| if (scr || s.textarea) { // see if user embedded response in textarea var ta = doc.getElementsByTagName('textarea')[0]; if (ta) { xhr.responseText = ta.value; } else if (scr) { // account for browsers injecting pre around json response var pre = doc.getElementsByTagName('pre')[0]; if (pre) { xhr.responseText = pre.innerHTML; }else xhr.responseText=doc.body.innerHTML; } } else if (s.dataType == 'xml' && !xhr.responseXML && xhr.responseText != null) { xhr.responseXML = toXml(xhr.responseText); } |
原文地址:http://www.v**i*fo.net/Program/JavaScript/10090191.shtml
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